SQL query to count in group by with specific condition

Question

My table data:

id      fieldId  Name   Text
----    ------  -----   ----
1        101    name1   a1
2        102    name2   a2
3        101    name1   a1
4               


        

Answer 1

Here.

SELECT
    `Name`,
    COUNT(*) AS 'fieldId',
    COUNT(IF(`Text` REGEXP '^a[1-3]',1,NULL)) AS 'a1a2a3'
FROM (SELECT * FROM `items` GROUP BY `Name`,`Text`) t1
GROUP BY `Name`;

Answer 2

select Name, 
    count(*) as CountAll, 
    count(case when Text like 'a1-%' or Text like 'a2-%' or Text like 'a3-%' then 1 end) as CountA1A2A3
from MyTable
group by Name

You could also use a RegEx if you wish.