How to fix dates to be similar format?

Question

I am receiving 2 date formats:

1/22/2020

1/22/20

I need to convert 1/22/2020 to 1/22/20

I currently use the

Answer 1

You can use php DateTime::createFromFormat function for converting the date in more robust way.

// filter only 4 digit year using regex
if (preg_match('/^\d{1,2}\/\d{1,2}\/\d{4}$/', $date)) {
    $dateObj = DateTime::createFromFormat('n/d/Y', $date);
    if ($dateObj === false) {
      throw new Exception("Not a valid date");
    }
    // convert it to 2 digit year
    echo $dateObj->format('n/j/y');
}

Here's how it can apply to your problem

<?php
    foreach($header as $field){
        if (preg_match('/^\d{1,2}\/\d{1,2}\/\d{4}$/', $field)) {
            $dateObj = DateTime::createFromFormat('n/d/Y', $field);

            if ($dateObj === false) {
                throw new Exception("Not a valid date");
            }
            // convert it to 2 digit year
            $field = $dateObj->format('n/j/y');

            if($insert){
                $days[] = ["date" => $field, $type => $value[$field]];
            }
            else{
                $date_index = array_search($field, array_column($globalData[$index]['data'], 'date'));

                $globalData[$index]['data'][$date_index][$type] = $value[$field];
            }
        }
    }

Answer 2

Do you need this:

$str1 = "1/22/2024";
$str2 = "1/22/24";



function get_needed_format($str) {
    if(strlen(explode("/", $str)[2]) === 4) {
        return substr($str, 0, -4).substr($str, -2);
    }

    return $str;
}


echo get_needed_format($str1);
echo "\n";
echo get_needed_format($str2);

?