Is there any way to use x:Name of the stacklayout in listview at code behind in xamarin.forms?
To be able to access templated elements by name and by whatever way you like, create a custom view that will serve You as a cell. And in the cell's code-behind you will be able to access everything by name. Your initial parent list will now look like:
<ListView HasUnevenRows="true" HeightRequest="{Binding ListHeight}">
<ListView.ItemTemplate>
<DataTemplate>
<user:MyViewCell/>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
Your brand new cell will look like:
XAML:
<?xml version="1.0" encoding="UTF-8"?>
<ViewCell xmlns="http://xamarin.com/schemas/2014/forms"
xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
x:Class="YourNameSpace.MyViewCell">
<StackLayout x:Name="btnStack" Spacing="0">
<Label x:Name="txtEvenMore"/>
</StackLayout>
</ViewCell>
Code:
namespace YourNameSpace
{
[XamlCompilation(XamlCompilationOptions.Compile)]
public partial class MyViewCell
{
public MyViewCell()
{
InitializeComponent();
//you can init your cells here
InitCell(); //this is just for demo
}
public void InitCell()
{
//i can access my stack:
btnStack.BackgroundColor = Color.Red;
//and even more
txtEvenMore.Text = "By name? Yes! :)";
}
//Now not for demo but in the real world:
//We can set content according to your data from ItemsSource
//This will act when you set your ListView ItemsSource to something valid
protected override void OnBindingContextChanged()
{
SetupCell();
base.OnBindingContextChanged();
}
public void SetupCell()
{
//use data from ItemsSource
var item = BindingContext as YourItemClass;
if (item == null) return;
txtEvenMore.Text = item.SomeTextProperty;
//etc.. :)
}
}
}
Good luck! :)
Because it is a ListView, there may be multiple StackLayouts. So what you need to do is give the ListView an x:Name property, and then you can access the items in the ListView using it's ItemSource
property. Like so:
<ListView HasUnevenRows="true" HeightRequest="{Binding ListHeight}" x:name="myListView">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<StackLayout>
<StackLayout />
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
Then in your code-behind, simply access the items through myListView.ItemsSource
.
If you really need to manipulate an individual StackLayout
in the list view, then you should think about setting it up properly using MVVM pattern.
When you define x:Name in Xaml, the relevant variable is defined automatically. So you can just use it as it was defined. Something like:
// StackLayout btnStack; // no need - it is defined already
var cnt = btnStack.Children.Count; // should be ok
Probably your problem is that in the line:
<StackLayout x:Name="btnStack/>
you forgot the closing quote. It should be:
<StackLayout x:Name="btnStack" />
This link explain how access elements withn listview ListView creates only one instance of each View Controls. We cannot access View Controls inside ListView directly. can be accessed indirectly.
<StackLayout VerticalOptions="FillAndExpand" HorizontalOptions="FillAndExpand">
<ListView x:Name="PersonListView" HasUnevenRows="True" SeparatorVisibility="Default">
<ListView.ItemTemplate>
<DataTemplate>
<ViewCell>
<StackLayout Orientation="Vertical" Padding="10" Margin="10">
<Label Text="{Binding name}" />
<Label Text="{Binding phone}" />
<Label Text="{Binding age}" />
<Button Text="Click to See" Clicked="DisplayData"/>
</StackLayout>
</ViewCell>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
async void DisplayData(object Sender, EventArgs e)
{
// access buttonclickhandler
var buttonClickHandler = (Button)Sender;
// access Parent Layout for Button
StackLayout ParentStackLayout = (StackLayout)buttonClickHandler.Parent;
// access first Label "name"
Label nameLabel = (Label)ParentStackLayout.Children[0];
// access second Label "phone"
Label phoneLabel = (Label)ParentStackLayout.Children[1];
// access third Label "age"
Label ageLabel = (Label)ParentStackLayout.Children[2];
string name = nameLabel.Text;
string phone = phoneLabel.Text;
string age = ageLabel.Text;
await DisplayAlert("Person Details", "Name is : " + name + ".\n Phone Number is: " + phone + "\n Age is : " + age, "OK");
}
https://www.xamarinpaul.com/2018/11/how-to-access-view-controls-inside-Xamarin-forms-ListView.html