How to select single quote mark exist records using oracle regex

Question

Table Name : Student

----------------
ID | NAME | ADDRESS
----------------
1 | Mark | Queen\'s Road
2 | Ann  | Church Road
3 | Sam  | Temple Road

I need to get si

Answer 1

im not sure about oracle but in Mysql following query will work for your purpose

select * from student where address like "%'%"

Answer 2

You can escape a quote in Oracle by doubling it.

So, using the regular LIKE operator:

SELECT * 
FROM student 
WHERE address LIKE '%''%'

With REGEXP_LIKE you'd have to perform a similar escaping:

SELECT * 
FROM student 
WHERE  regexp_like (address, '''+')