split semicolon delimiter SQL to rows [duplicate]

Answer 1

Option 1 with a UDF

Declare @YourTable table (ID int, Value varchar(max))
Insert Into @YourTable values
(1,'A&B;C;D;E, F')

Select A.ID
      ,B.*
 From @YourTable A
 Cross Apply [dbo].[udf-Str-Parse-8K](A.Value,';') B

Option 2 without a UDF

Select A.ID
      ,B.*
 From @YourTable A
 Cross Apply (
                Select RetSeq = Row_Number() over (Order By (Select null))
                      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                From  (Select x = Cast('<x>' + replace((Select replace(A.Value,';','§§Split§§') as [*] For XML Path('')),'§§Split§§','</x><x>')+'</x>' as xml).query('.')) as A 
                Cross Apply x.nodes('x') AS B(i)
              ) B

Both Return

ID  RetSeq  RetVal
1   1       A&B
1   2       C
1   3       D
1   4       E, F

This UDF is XML Safe and VERY fast

CREATE FUNCTION [dbo].[udf-Str-Parse-8K] (@String varchar(max),@Delimiter varchar(25))
Returns Table 
As
Return (  
    with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
           cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 a,cte1 b,cte1 c,cte1 d) A ),
           cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter)) = @Delimiter),
           cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter,@String,s.N),0)-S.N,8000) From cte3 S)

    Select RetSeq = Row_Number() over (Order By A.N)
          ,RetVal = LTrim(RTrim(Substring(@String, A.N, A.L)))
    From   cte4 A
);
--Orginal Source http://www.sqlservercentral.com/articles/Tally+Table/72993/
--Much faster than str-Parse, but limited to 8K
--Select * from [dbo].[udf-Str-Parse-8K]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse-8K]('John||Cappelletti||was||here','||')

Answer 2

Please use the function below to split a string by a specific delimiter:

CREATE FUNCTION [dbo].[Split](@String varchar(8000), @Delimiter char(1))        
returns @temptable TABLE (SplitValue varchar(8000))        
as        
begin        
    declare @idx int        
    declare @slice varchar(8000)        

    select @idx = 1        
       if len(@String)<1 or @String is null  return        

    while @idx!= 0        
    begin        
        set @idx = charindex(@Delimiter,@String)        
        if @idx!=0        
            set @slice = left(@String,@idx - 1)        
        else        
            set @slice = @String        

        if(len(@slice)>0)   
            insert into @temptable(SplitValue) values(@slice)        

        set @String = right(@String,len(@String) - @idx)        
        if len(@String) = 0 break        
    end    
return       
end

Let me know if you have any queries.

Thanks .

Answer 3

If you do not like a function, or if you do not have the rights to create a new function, you can use the quite fast XML approach. In your case it needs some extra effort to get this XML-safe (due to special characters and the ; as delimiter):

Declare @Dummy table (ID int, SomeTextToSplit varchar(max))
Insert Into @Dummy values
 (1,'A&B;C;D;E, F')
,(2,'"C" & "D";<C>;D;E, F');

DECLARE @Delimiter VARCHAR(10)=';';
WITH Casted AS
(
    SELECT *
          ,CAST('<x>' + REPLACE((SELECT REPLACE(SomeTextToSplit,@Delimiter,'§§Split$me$here§§') AS [*] FOR XML PATH('')),'§§Split$me$here§§','</x><x>') + '</x>' AS XML) AS SplitMe
    FROM @Dummy
)
SELECT Casted.*
      ,x.value('.','nvarchar(max)') AS Part 
FROM Casted
CROSS APPLY SplitMe.nodes('/x') AS A(x)

The result

1   A&B
1   C
1   D
1   E, F
2   "C" & "D"
2   <C>
2   D
2   E, F