php/mysql. Is there mysql function to detect if at least 2 certain words exists in at least one mysql row-field

Question

For example, I have php array $php_arr_to_check = array(\"green\", \"red\", \"blue\");

And have many mysql rows like this

Id  |  TextToCheck         


        

Answer 1

I think you want to use Boolean Full-Text Search

If you match without operators + - against such as green red blue all rows are returned, where a record contains at least one word: green or red or blue.

IN BOOLEAN MODE and without operators each matched word will score 1. So if there's a record matching two out of the three words it would score 2.

To get the rows with at least 2 score:

SELECT *,
MATCH (`TextToCheckIn`) AGAINST ('green red blue' IN BOOLEAN MODE) `score`
FROM `my_tab` WHERE 
MATCH (`TextToCheckIn`) AGAINST ('green red blue' IN BOOLEAN MODE)
HAVING `score` >= 2
ORDER BY `score` DESC

In Natural Language mode scoring works completely different. Think it's primarily based on BM25.

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On large datasets boolean fulltext search (using a fulltext index) usually outperforms REGEXP or LIKE by far if matching words somewhere in the text. Would only use like/regexp for matching from the initial such as REGEXP '^word' or LIKE 'word%' - if an index can be utilized.

Answer 2

I haven't MySQL for to test next query. You try something:

SELECT Id, TextToCheckIn REGEXP "(${word1})|(${word2})" AS Flag
FROM table
WHERE Flag = 1