pivot html table using php

Question

I have this php code:

$query_production = \"SELECT uploadedby as name, sum(points) as points,
date_format(uploaddate,\'%Y-%m-%d\') as date FROM imsexport 
WHERE          


        

Answer 1

This will get you most of the way there; what I've left to you is how to get the left offset correct (or the date/points column alignment; hint, you'll need to keep the date with the name/points pair and know it's offset in $cols).

Obviously you're dealing with rows out of a database, so it'll be a little bit different.

See the codepad demo link below the code.

<?php

$data = "John 147 2014-01-01
Bob 79 2014-01-01
Joe 156 2014-01-01
Sue 116 2014-01-01
John 117 2014-01-02
Bob 186 2014-01-02
Sue 74 2014-01-02
Bob 233 2014-01-03
John 159 2014-01-03
Sue 162 2014-01-03
Bob 162 2014-01-04
Sue 38 2014-01-05";

$data = explode("\n", $data);

$cols = array();
$pivot = array();

while ($line = array_shift($data)) {
    list($name, $points, $date) = explode(' ', trim($line));

    if (!$pivot[$name]) $pivot[$name] = array();

    array_push($cols, $date);

    array_push($pivot[$name], array('date' => $date, 'points' => $points));
}

$cols = array_unique($cols);

print_r($pivot);

echo implode('|', $cols);

echo PHP_EOL;

foreach ($pivot as $name => $row) {
    while ($entry = array_shift($row)) {
        echo str_pad($name, 7, ' ') . str_pad($entry['points'], 3, ' ', STR_PAD_LEFT) . '|';
    }

    echo PHP_EOL;
}

?>

http://codepad.org/WqqpKwn3