Put command output into a variable

Question

Given a directory with the following files

image1.txt
image2.txt
image3.txt

I want to get the oldest file (let the files be sorted by data, old

Answer 1

There isn't a direct way, the FOR-Loop is one way or the other way is set /p with a temporary file.

dir /b /od c:\test\image?.txt | findstr ^1 > oldest.tmp
< oldest.tmp set /p myVar=

Answer 2

Example:

wmic path Win32_VideoController get CurrentHorizontalResolution | FINDSTR [0-9] > X.txt 'Output in a file
wmic path Win32_VideoController get CurrentVerticalResolution | FINDSTR [0-9] > Y.txt
wmic path Win32_VideoController get CurrentRefreshRate | FINDSTR [0-9] > Hz.txt
wmic path Win32_VideoController get CurrentBitsPerPixel | FINDSTR [0-9] > Bits.txt
set /p X= < X.txt 'Input from a file
set /p Y= < Y.txt
set /p Hz= < Hz.txt
set /p Bits= < Bits.txt
set X=%X: =% 'Remove the spaces
set Y=%Y: =%
set Hz=%Hz: =%
set Bits=%Bits: =%
DEL /q X.txt 'Delete file created
DEL /q Y.txt
DEL /q Hz.txt
DEL /q Bits.txt

Four steps.

Answer 3

set variableName = dir /b /od C;\test\image?.txt | findstr ^1

note: this is untested. Source:

Google

Answer 4

For /F %%A in ('"dir /b /od C:\test\image*.txt|findstr ^1"') do set myVar=%%A

You could do it through For loop, try that in command line, I just tested it and it works fine

Output:

set myVar=image1.txt

On executing Set on command line you can see:

myVar=image1.txt
NUMBER_OF_PROCESSORS=2