Finding duplicate values

Question

I have a table called Transfers, and I would like to find all the records that have duplicate values on three columns Doc ID,Amount and Date. Basically what I need is to find w

Answer 1

Use This:

select transfers.doc_id,transfers.date,transfers.amount,count(*) counts
from transfers
group by doc_id,date,amount
having counts>1;

Output will be with Count of duplicate Records:

doc_id  date        amount  counts
1234    12/07/2019  3,000   2
2345    12/07/2019  15,000  2
4321    12/07/2019  5,600   2

Answer 2

Consider using group by for three columnsgroup by doc_id,Amount,Date

select t.doc_id,t.date,t.amount
  from transfers t
 where t.date between $P{StartDate} and $P{EndDate}
 group by doc_id,Amount,Date
having count(doc_id) >1;