Regex doesn't omit quotes when matching text in quotes

Question

I\'m trying to do a non-greedy capture of text inside double quotation marks with regex in node.js. Most of the Google results say I should use one of these:

\"         


        

Answer 1

match method returns an array of just matches. See MDN:

Captured groups are not returned.

A fix is to use exec:

var re = /"(.*?)"/g; 
var str = '|>  "Song" by "Artist" on "Album" <3';
 
while ((m = re.exec(str)) !== null) {
    document.getElementById("res").innerHTML += m[1] + "<br />";
}

<div id="res"/>

Answer 2

You can give this a shot. This should include everything in the quotes but not the quotes themselves -

/(?<=")[^" ]*(?=")/ 

Answer 3

Your regex is looking for, and matching quotes. You can do this to modify the value matched to effectively trim off the quotes.

var testStr = '|>  "Song" by "Artist" on "Album" <3';
var regex = /"([^"]*)"/g; // or /"(.*?)"/g
var info = testStr.match(regex).map(function (o) {
  return o.substr(1,o.length-2)
});
if (info){
    console.dir(info[0]);
    console.dir(info[1]);
    console.dir(info[2]);
}