How to convert hex string 'o\xf2\x00\x00' into a int32?

Question

When I read first 4 bytes with python code

len = fobj.read(4)

I got \'o\\xf2\\x00\\x00\'. This should be an int32, an

Answer 1

I Tried this and got the answer:

>>> print(int.from_bytes(b'o\xf2\x00\x00','little'))
62063

Answer 2

>>> import struct
>>> struct.unpack('<i', 'o\xf2\x00\x00')
(62063,)