how can we group 5 pm yesterday to 5 pm today records to todays date

Question

oracle table

id  timestamp                status
1  2019-10-20 12:34:56.000   approved
1  2019-10-22 12:34:56.000   approved
2  2019-10-20 17:34:56.000   approv         


        

Answer 1

If you want to treat 5pm to 5pm as the "same" day, it is easy to shift an Oracle date either forward or backward with fractions of day, (eg 5pm can be shifted 7 hours forward to become the start of the 'next' day)

SQL> create table ora_table (id number, time_data timestamp, status varchar2(30));

Table created.

SQL> insert into ora_table values (1  , to_timestamp('2019-10-20 12:34:56.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (1  , to_timestamp('2019-10-22 12:34:56.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (2  , to_timestamp('2019-10-20 17:34:56.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (2  , to_timestamp('2019-10-21 12:34:56.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (3  , to_timestamp('2019-10-23 18:10:10.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'mod_in_ip');

1 row created.

SQL> insert into ora_table values (3  , to_timestamp('2019-10-24 11:10:10.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (3  , to_timestamp('2019-10-24 12:10:10.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (4  , to_timestamp('2019-10-25 12:10:10.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL> insert into ora_table values (4  , to_timestamp('2019-10-25 18:10:10.000', 'yyyy-mm-dd hh24:mi:ss.ff'), 'approved');

1 row created.

SQL>
SQL> select id, time_data, trunc(time_data) true_date, trunc(time_data+7/24) mapped_date
  2  from ora_table;

        ID TIME_DATA                          TRUE_DATE MAPPED_DA
---------- ---------------------------------- --------- ---------
         1 20-OCT-19 12.34.56.000000 PM       20-OCT-19 20-OCT-19
         1 22-OCT-19 12.34.56.000000 PM       22-OCT-19 22-OCT-19
         2 20-OCT-19 05.34.56.000000 PM       20-OCT-19 21-OCT-19 <===
         2 21-OCT-19 12.34.56.000000 PM       21-OCT-19 21-OCT-19
         3 23-OCT-19 06.10.10.000000 PM       23-OCT-19 24-OCT-19 <===
         3 24-OCT-19 11.10.10.000000 AM       24-OCT-19 24-OCT-19
         3 24-OCT-19 12.10.10.000000 PM       24-OCT-19 24-OCT-19
         4 25-OCT-19 12.10.10.000000 PM       25-OCT-19 25-OCT-19
         4 25-OCT-19 06.10.10.000000 PM       25-OCT-19 26-OCT-19

9 rows selected.

Answer 2

This should give you what you're looking for:

WITH cte(id, ts, NewCutoff, Row_Num) AS (
  select 
    id, 
    ts, 
    MIN(
      trunc(ts) + 
      CASE 
        WHEN EXTRACT(HOUR FROM ts) < 17 THEN INTERVAL '00 17' DAY TO HOUR
        ELSE INTERVAL '01 17' DAY TO HOUR -- If time is after 5pm, add an extra day
      END
    ) OVER(PARTITION BY id) AS NewCutoff, -- Determine cut-off TS for "new" entries
    ROW_NUMBER() OVER(
      PARTITION BY id ORDER BY ts DESC
    ) AS Row_Num -- Order entries by date within "id" group
  FROM mytable
)
SELECT id, CASE WHEN ts < NewCutoff THEN 'new' ELSE 'edited' END AS prefix
FROM cte
WHERE Row_Num = 1 -- Only look at latest entry per id
;

You may need to check the end conditions -- i.e. how to handle a ts value with exactly 5pm.

SQL Fiddle