Regular Expression Matching -Java

Question

I am taking input from a file in following format:

(int1,int2) (int3,int4)

Now I want to read int1, int2, int3 and int4 in my Java code. How ca

Answer 1

Pattern p = Pattern.compile("\\((\\d+),(\\d+)\\)\\s+\\((\\d+),(\\d+)\\)");
String input = "(123,456) (789,012)";

Matcher m = p.matcher(input);

if (m.matches()) {
  int a = Integer.parseInt(m.group(1), 10);
  int b = Integer.parseInt(m.group(2), 10);
  int c = Integer.parseInt(m.group(3), 10);
  int d = Integer.parseInt(m.group(4), 10);
}

Answer 2

To build on your own method, you can use a much simpler regex:

String s = "(1,2) (3,4)";
Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher(s);
while (m.find()) {
    System.out.println(m.group());
}

Answer 3

You could do something like:

String str = "(1,2) (3,4)";
Matcher m = Pattern.compile("\\((\\d+),(\\d+)\\) \\((\\d+),(\\d+)\\)").matcher(str);
if (m.matches()) {
   System.out.println(m.group(1)); // number 1
   ...
}

Answer 4

String[] ints = "(2,3) (4,5)".split("\\D+");
System.out.println(Arrays.asList(ints));
// prints [, 2, 3, 4, 5]

To avoid empty values:

String[] ints = "(2,3) (4,5)".replaceAll("^\\D*(.*)\\D*$", "$1").split("\\D+");
System.out.println(Arrays.asList(ints));
// prints [2, 3, 4, 5]

Answer 5

"\\((\\d*),(\\d*)\\)\\s*\\((\\d*),(\\d*)\\)"

Answer 6

This will work:

String[] values = s.substring(1).split("\\D+");