From the docs page http://php.net/manual/en/language.oop5.typehinting.php
If class or interface is specified as type hint then all its children or implementations are al
From the same typehinting section you linked to:
The class implementing the interface must use the exact same method signatures as are defined in the interface. Not doing so will result in a fatal error.
For the method signatures to be the same, they must contain the exact same typehints. And also relevant because it is similar...
From the OOP Basics - extends section of the manual:
When overriding methods, the parameter signature should remain the same or PHP will generate an
E_STRICT
level error. This does not apply to the constructor, which allows overriding with different parameters.
If I am not mistaken you get this error:
Declaration of PimpleConfigurer_Factories::configure() must be compatible with Pimple_Config::configure(Pimple $container) ...
Which means: If you define a method in a super class or in an interface, all sub classes (or classes implementing the interface) must use exactly this definition. You cannot use another type here.
As for your quote from the documentation:
If class or interface is specified as type hint then all its children or implementations are allowed too.
This only means that you can pass a variable which is of a certain type or all its children.
For example: Say you have the following classes:
class Car {
protected $hp = 50;
public function getHp() { return $this->hp; }
}
class SuperCar extends Car {
protected $hp = 700;
}
And a function (or method, no difference there) with type hint:
function showHorsePower(Car $car) {
echo $car->getHp();
}
You can now pass all objects of type Car and all its sub classes (here SuperCar) to this function, like:
showHorsePower(new Car());
showHorsePower(new SuperCar());