Get multiple numbers from a string

Question

I have strings like

AS_!SD 2453iur ks@d9304-52kasd

I need to get the 2 frist numbres of the string:

for that case will be:

Answer 1

You can loop chars of your string parsing them, if you got a exception thats a letter if not is a number them you must to have a list to add this two numbers, and a counter to limitate this.

follow a pseudocode:

for char in string:

if counter == 2:
 stop loop

if parse gets exception
 continue

else
 loop again in samestring stating this point
 if parse gets exception
  stop loop
 else add char to list

Answer 2

Alternatively you can use the ASCII encoding:

string value = "AS_!SD 2453iur ks@d9304-52kasd";

byte zero = 48; // 0
byte nine = 57; // 9

byte[] asciiBytes = Encoding.ASCII.GetBytes(value);

byte[] asciiNumbers = asciiBytes.Where(b => b >= zero && b <= nine)
                    .ToArray();

char[] numbers = Encoding.ASCII.GetChars(asciiNumbers);

// OR

string numbersString =  Encoding.ASCII.GetString(asciiNumbers);

//First two number from char array
int aNum = Convert.ToInt32(numbers[0]);
int bNum =  Convert.ToInt32(numbers[1]);

//First two number from string
string aString = numbersString.Substring(0,2);

Answer 3

This solution will take two first numbers, each can have any number of digits

string s =  "AS_!SD 2453iur ks@d9304-52kasd";

MatchCollection matches = Regex.Matches(s, @"\d+");

string[] result = matches.Cast<Match>()
                         .Take(2)
                         .Select(match => match.Value)
                         .ToArray();

Console.WriteLine( string.Join(Environment.NewLine, result) );

will print

2453
9304

you can parse them to int[] by result.Select(int.Parse).ToArray();