When using .index in a list only returns first time it appears in the array

Question

sentence = \"ask not what your country can do for you ask what you can do for your country\"
sentList = sentence.split()

print(sentence)
userWord = input(\"Pick a word          


        

Answer 1

list.index accepts additional start index (and end index). Pass the index to find next matched item index.

...

if userWord in sentList:
    i = 0
    while True:
        try:
            i = sentList.index(userWord, i)  # <---
        except ValueError:  # will raise ValueError unless the item is found
            break
        i += 1
        print("{} appears in the sentence in the {}th position".format(
            userWord, i
        ))

else:
     ....

Answer 2

The other answer is better. I left this one as an example of an alternative way.

according to the python documentation at https://docs.python.org/3.3/tutorial/datastructures.html

Index: Return the index in the list of the first item whose value is x. It is an error if there is no such item.

you should probably use a for loop (the easiest way) or probably it will be a good example of writing a generator.

for i,word in enumerate(sentList):
    if userWord == word:
        checkLocation(i,userWord)

def checkLocation(index,userWord):
    if index + 1 >= 4:
        print (userWord, "appears in the sentence in the",index + 1,"th position")
    elif 
        index + 1 == 3:
        print (userWord, "appears in the sentence in the",index + 1,"rd position")
    elif 
        index + 1 == 2:
        print (userWord, "appears in the sentence in the",index + 1,"nd position")
    elif 
        index + 1 == 1:
        print (userWord, "appears in the sentence in the",index + 1,"st position")