PostgreSQL: Returning the most recent rows grouping by a foreign key column

Question

I have a table that looks similar to this:

credit
+---------+----------------+-------------+--------------+-------------------------+
| id (PK) | person_id (FK)          


        

Answer 1

Use distinct on:

select distinct on (person_id) t.*
from t
order by person_id, date_time desc

Answer 2

You can try this. use ROW_NUMBER with window function to make row number split by person_id and order by date_time in subquery then get row number is 1

CREATE TABLE credit(
   id int,
   person_id int,
   transaction float,
   "total credit" float,
   date_time timestamp
);

INSERT INTO credit values (345,1 ,-1.00,34.50, '2018-08-29 12:00:00.000');
INSERT INTO credit values (897,1 ,5.45 ,39.95, '2018-08-29 12:34:00.000');
INSERT INTO credit values (378,2 ,0.01 ,0.01 , '2018-08-29 08:00:00.000');
INSERT INTO credit values (789,2 ,20.00,20.01, '2018-08-29 09:00:00.000');

Query 1:

SELECT * FROM (
    SELECT *,ROW_NUMBER() OVER (PARTITION BY person_id  ORDER BY date_time DESC) rn
    FROM credit
) t1
where rn = 1

Results:

|  id | person_id | transaction | total credit |            date_time | rn |
|-----|-----------|-------------|--------------|----------------------|----|
| 897 |         1 |        5.45 |        39.95 | 2018-08-29T12:34:00Z |  1 |
| 789 |         2 |          20 |        20.01 | 2018-08-29T09:00:00Z |  1 |