C# While TryParse

Question

char typeClient = \' \';
bool clientValide = false;
while (!clientValide)
{
     Console.WriteLine(\"\\nEntrez le type d\'employé (c ou g) : \");
     clientValide = cha         


        

Answer 1

You're really close, I think something like this will work well for you:

char typeClient = ' ';
while (typeClient != 'c' && typeClient != 'g')
{
    Console.WriteLine("\nEntrez le type d'employé (c ou g) : ");
    var line = Console.ReadLine();
    if (!string.IsNullOrEmpty(line)) { typeClient = line[0]; }
    else { typeClient = ' '; }
}

basically it reads the input into the typeClient variable when the user enters something so the loop will continue until they enter g or c.

Answer 2

Is you use Console.ReadLine, the user has to press Enter after pressing c or g. Use ReadKey instead so that the response is instantaneous:

bool valid = false;
while (!valid)
{
    Console.WriteLine("\nEntrez le type d'employé (c ou g) : ");
    var key = Console.ReadKey();
    switch (char.ToLower(key.KeyChar))
    {
        case 'c':
            // your processing
            valid = true;
            break;
        case 'g':
            // your processing
            valid = true;
            break;
        default:
            Console.WriteLine("Invalid. Please try again.");
            break;
    }
}

Answer 3

You can use ConsoleKeyInfo with Console.ReadKey() :

 ConsoleKeyInfo keyInfo;
 do {
   Console.WriteLine("\nEntrez le type d'employé (c ou g) : ");
   keyInfo = Console.ReadKey();
 } while (keyInfo.Key != ConsoleKey.C && keyInfo.Key != ConsoleKey.G);
   

Answer 4

string input;
do {
    Console.WriteLine("Entrez le type d'employé (c ou g):");
    input = Console.ReadLine();
} while (input != "c" && input != "g");

char typeClient = input[0];