Creating 8 bit image from byte array

Question

The byte array is obtained this way -

BufferedImage image = new Robot().createScreenCapture(new Rectangle(screenDimension));
byte[] array = ((DataBufferByte)getG         


        

Answer 1

You have to specify the correct ColorSpace corresponding to a grayscale image.

Here's an example, as found on http://technojeeves.com/joomla/index.php/free/89-create-grayscale-image-on-the-fly-in-java:

public static BufferedImage getGrayscale(int width, byte[] buffer) {
    int height = buffer.length / width;
    ColorSpace cs = ColorSpace.getInstance(ColorSpace.CS_GRAY);
    int[] nBits = { 8 };
    ColorModel cm = new ComponentColorModel(cs, nBits, false, true,
            Transparency.OPAQUE, DataBuffer.TYPE_BYTE);
    SampleModel sm = cm.createCompatibleSampleModel(width, height);
    DataBufferByte db = new DataBufferByte(buffer, width * height);
    WritableRaster raster = Raster.createWritableRaster(sm, db, null);
    BufferedImage result = new BufferedImage(cm, raster, false, null);

    return result;
}

Answer 2

I hope it'll help you if I explain to you how to convert from ARGB/RGB 2 gray cause there are too many unknown functions and classes :P

ARGB is 32 bit/pixel so 8 bit for every channel. the alpha channel is the opacity so the opposite of transparency so 0 is transparent.

RGB is 24 bit/pixel. to convert from ARGB to RGB you have to dismiss the alpha channel.

to convert from RGB to grayscale u have to use this formula:

0.2989 * R + 0.5870 * G + 0.1140 * B

so you have to figure out which byte belongs to which channel ;)

Answer 3

This will work. Just make sure you tweak the image type the way you need:

Image img = new ImageIcon(array).getImage();
BufferedImage image = new BufferedImage(img.getWidth(null), img.getHeight(null), BufferedImage.TYPE_INT_ARGB);
image.createGraphics().drawImage(img, 0, 0, null);