I understand that two functions can run in parallel using multiprocessing
or threading
modules, e.g. Make 2 functions run at the same time and Python m
Target should only receive the function name. The parameters should be passed with the parameter "args". I cannot paste the code because I am answering from my mobile phone... ;-)
Thread's target function cannot return a value. Or, I should say, the return
value is ignored and as such, not communicated back to spawning thread. But here's a couple things you can do:
1) Communicate back to spawning thread using Queue.Queue
. Note the wrapper around the original functions:
from threading import Thread
from Queue import Queue
def func1(x):
return [i*i for i in x]
def func2(x):
return [i*i*i for i in x]
nums = [1,2,3,4,5]
def wrapper(func, arg, queue):
queue.put(func(arg))
q1, q2 = Queue(), Queue()
Thread(target=wrapper, args=(func1, nums, q1)).start()
Thread(target=wrapper, args=(func2, nums, q2)).start()
print q1.get(), q2.get()
2) Use global
to access result lists in your threads, as well as the spawning process:
from threading import Thread
list1=list()
list2=list()
def func1(x):
global list1
list1 = [i*i for i in x]
def func2(x):
global list2
list2 = [i*i*i for i in x]
nums = [1,2,3,4,5]
Thread(target = func1, args=(nums,)).start()
Thread(target = func2, args=(nums,)).start()
print list1, list2