Warning: Invalid argument supplied for foreach() in

Question

$results = mysql_query(\"select * from classpics\");

foreach($results as $uno) {
    echo \'

        

Answer 1

mysql_query returns resource, not an array or any other container. Use mysql_fetch_assoc() to fetch the next result.

while ($uno = mysql_fetch_assoc($result)) {
    echo '<td valign="middle" align="center"><a class="neutral" href="../images.php?id=' . $uno['id'] . '"><img src="'. $uno['thumbs'].'" border="0" /></a>';
}

Answer 2

The mysql_query returns a resource id, you should fetch an array:

$results = mysql_query("select * from classpics");

while($row = mysql_fetch_array($results)){
  echo '<td valign="middle" align="center"><a class="neutral" href="../images.php?id=' . $row['id'] . '"><img src="'. $row['thumbs'].'" border="0" /></a>';
}

Answer 3

you should fetch data from result

while($data=mysql_fetch_array($results)) {
echo '<td valign="middle" align="center"><a class="neutral" href="../images.php?id=' . $uno['id'] . '"><img src="'. $uno['thumbs'].'" border="0" /></a>';

}