I have a list of floats which comes from some other function. What I know is that in ideal world there exist a common factor which can be used to multiply each term to obtain li
The brute force solution. Still looking for something more universal...
def find_int(arr):
test = False
epsilon = 1e-15
maxint = 1000
for i in range(2, maxint, 1):
for item in arr:
if abs(i*item-round(i*item)) < epsilon:
test = True
else:
test = False
break
if test:
print i
return [int(round(i*item)) for item in arr]
print "Could not find one"
return arr
Python's Fraction type can convert floating points to rationals with denominators under 1000000, and then you can find the lowest common denominator.
>>> from fractions import Fraction
>>> a = [2.3333333333333335, 4.666666666666667, 1.0, 1.6666666666666667]
>>> [Fraction(x).limit_denominator() for x in a]
[Fraction(7, 3), Fraction(14, 3), Fraction(1, 1), Fraction(5, 3)]
A straightforward way to find the least common multiple using the math.gcd function:
>>> denoms = [3,3,1,2]
>>> functools.reduce(lambda a,b: a*b//math.gcd(a,b), denoms)
6