using django rest framework to return info by name

Question

I am using Django rest framework and I create this class to return all the name of project

class cpuProjectsViewSet(viewsets.ViewSet):
  serializer_class = seri         


        

Answer 1

One does not use raw queries unless absolutely needed and even then, there isn't a need to manually connect to the database because you have easy access to a connection object. Overall, your retrieve method can be improved as follows:

def retrieve(self, request, pk=None):
    queryset = CpuProject.objects.all()
    cpu = get_object_or_404(queryset, pk=pk)
    serializer = serializers.cpuProjectsSerializer(cpu)
    return Response(serializer.data)

Much shorter and easier to read. But Even this is not really needed If you use a ModelViewset! Then the default retrieve method will take care of this for you. So your viewset reduces to

class cpuProjectsViewset(viewsets.ModelViewSet):
    serializer_class =serializer = serializers.cpuProjectsSerializer
    queryset = CpuProject.objects.all()

You don't need a retrieve method here!!

But I see that you are trying to retrieve a particular CpuProject item by it's name (rather than using it's PK). For that you need to add a route

from rest_framework.decorators import detail_route, list_route
@detail_route(url_path='(?P<slug>[\w-]+)')
def get_by_name(self, request, pk=None,slug=None):

    queryset = CpuProject.objects.all()
    cpu = get_object_or_404(queryset, name=slug)
    serializer = serializers.cpuProjectsSerializer(cpu)
    return Response(serializer.data)

Answer 2

If you want to use the same class you can use a viewset and define a list() and retrieve() methods

check http://www.django-rest-framework.org/api-guide/viewsets/ the first example is doing that

from django.contrib.auth.models import User
from django.shortcuts import get_object_or_404
from myapps.serializers import UserSerializer
from rest_framework import viewsets
from rest_framework.response import Response

class UserViewSet(viewsets.ViewSet):
    """
    A simple ViewSet for listing or retrieving users.
    """
    def list(self, request):
        queryset = User.objects.all()
        serializer = UserSerializer(queryset, many=True)
        return Response(serializer.data)

    def retrieve(self, request, pk=None):
        queryset = User.objects.all()
        user = get_object_or_404(queryset, pk=pk)
        serializer = UserSerializer(user)
        return Response(serializer.data)

Answer 3

You need to add lookup_field in view class. Suppose, you want to get user by username you need to add lookup_field = 'username'.

Example:

from django.contrib.auth.models import User
from django.shortcuts import get_object_or_404
from myapps.serializers import UserSerializer
from rest_framework import viewsets
from rest_framework.response import Response

class UserViewSet(viewsets.ViewSet):

    lookup_field = 'username'

    def list(self, request):
        queryset = User.objects.all()
        serializer = UserSerializer(queryset, many=True)
        return Response(serializer.data)

    def retrieve(self, request, username=None):
        queryset = User.objects.all()
        user = get_object_or_404(queryset, username=username)
        serializer = UserSerializer(user)
        return Response(serializer.data)

Now your url will be

url(r'^users/$', UserViewSet.as_view({'get': 'list'})),
url(r'^users/(?P<username>[a-zA-Z0-9]+)$', UserViewSet.as_view({'get': 'retrieve'})),

Now http://127.0.0.1:8000/users/ will return all users and http://127.0.0.1:8000/users/username will return particular user details.

You can learn more about lookup_field from Django REST framework.