is there anything similar to Java's string 'charAt()' Method in C?

Question

I\'m trying to convert a piece of code from Java to C and I got stuck here, trying to get a character at each position.

char ch;

line += \' \';
    while (pos          


        

Answer 1

in C, the easiest way to get a char from an array of character (I.E. a string)

given the variables in your posted code,

char ch;

line += ' ';
while (pos < line.length()) 
{
    ch = line.charAt(pos);  
...

1. assuming that the string is terminated with a NUL byte ('\0')
2. assuming there is room in the line[] array for another character

would become:

#include <string.h>
strcat( line, " ");
size_t maxPos = strlen( line );
for( pos = 0; pos < maxPos; pos++ )
{
    ch = line[pos];
....

Answer 2

You can get a character at specific position in this way

char str[] = "Anything";
printf("%c", str[0]);

but when you have a pointer array:

char* an_array_of_strings[]={"balloon", "whatever", "isnext"};
cout << an_array_of_strings[1][2] << endl;

If you need to change the strings use

char an_array_of_strings[][20]={"balloon", "whatever", "isnext"};
cout << an_array_of_strings[1][2] << endl;

source: here

Answer 3

You can access the values as though the String was an array.

char str[] = "Hello World";
printf("%c", str[0]);