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PHP - form action calling itself, how to display everything in 1 page?

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暖寄归人
暖寄归人 2021-01-22 14:43

I have two .php files as such:

test1.php



    Sample
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9条回答
  • 深忆病人
    2021-01-22 15:33

    This one is fully tested and allows you to revise the value after submission. You still have to worry about cross-site scripting attacks, etc... but that is outside of the scope of the question.

    <html>
<head>
    <title>Sample</title>
</head>
<body>
    <?php
    $user_number = '';
    if (isset($_POST['userNumber'])) {
        $user_number=$_POST['userNumber'];
    ?>
    <p>You have chosen <?php echo $user_number ?></p>
    <?php
    }
    ?>
    <form method="post">
    Please enter a number <input type="number" name="userNumber" value="<?php echo $user_number ?>"><br>
    <input type="submit">
    </form>
</body>
</html>
    0 讨论(0)
  • 时光取名叫无心
    2021-01-22 15:36

    Check if $_POST["userNumber"] isset, and echo the form if it's not.

    <html>
<head>
    <title>Sample</title>
</head>
<body>
    <?php
        if(isset($_POST["userNumber"]){
            echo "You have chosen ".$_POST["userNumber"];
        }else{
            echo '<form action="test1.php" method="post">';
            echo 'Please enter a number <input type="number" name="userNumber"><br>';
            echo '<input type="submit">';
            echo '</form>';
        }
    ?>
</body>
</html>
    0 讨论(0)
  • 没有蜡笔的小新
    2021-01-22 15:36

    You simply need to remove the action="test2.php" section and combine both pages into one just like the following:

    <html>
<head>
    <title>Sample</title>
</head>
<body>
    <form method="post">
        Please enter a number <input type="number" name="userNumber"><br>
        <input type="submit">
    </form>

<?php
    if(isset($_POST['userNumber'])){
        $user_number = $_POST['userNumber'];
        echo "You have chosen $user_number";
    }
?>
</body>
</html>
    0 讨论(0)
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