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PHP - form action calling itself, how to display everything in 1 page?

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暖寄归人
暖寄归人 2021-01-22 14:43

I have two .php files as such:

test1.php



    Sample
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9条回答
  • [愿得一人]
    2021-01-22 15:14

    Sample 

    <form action="<?php $_PHP_SELF ?>" method="post">
    Please enter a number <input type="number" name="userNumber"><br>
    <input type="submit">
</form>
 </body> </html>
    0 讨论(0)
  • 盖世英雄少女心
    2021-01-22 15:17 
    <html>
<head>
<title>Sample</title>
</head>

<body>
<?php   
    if (isset($_POST['submitted'])) { 
    $user_number = $_POST["userNumber"];
    echo "You have chosen $user_number";    
    }
else {
?>
<form method="post">
    Please enter a number <input type="number" name="userNumber"><br>
    <input type="submit" name="submitted">
</form>
<?php
}
?>

</body>
</html>
    0 讨论(0)
  • 长情又很酷
    2021-01-22 15:17

    set the variables up before the form as placeholders and check for isset

    <?php
$user_number = '';
if(isset($_POST["userNumber"])) { 
    $user_number = $_POST["userNumber"];
}
?>

<form action="test2.php" method="post">
    Please enter a number <input type="number" name="userNumber"><br>
    <input type="submit" name="submit">
</form>

<p>You have chosen: <?php echo $user_number ?></p>
    0 讨论(0)
  • 时光说笑
    2021-01-22 15:22

    Just use isset() for submit button, note that i added name="submit" to your button since it was missing

    <html>
<head>
    <title>Sample</title>
</head>
<body>
<?php   
if(isset($_POST['submit'])
{
    $user_number = $_POST["userNumber"];
    echo "You have chosen $user_number";    
} else {
?>
    <form action="test2.php" method="post">
        Please enter a number <input type="number" name="userNumber"><br>
        <input type="submit" name="submit">
    </form>
<?php } ?>
</body>
</html>
    0 讨论(0)
  • 生来不讨喜
    2021-01-22 15:28

    Pretty simple actually:

       <html>
    <head>
        <title>Sample</title>
    </head>
    <body>
        <?php   
        if(isset($_POST) && isset($_POST['userNumber'])) {
            $user_number = $_POST["userNumber"];
            echo "You have chosen $user_number";    
        }
        ?>
        <form method="post">
            Please enter a number <input type="number" name="userNumber"><br>
            <input type="submit">
        </form>
    </body>
    </html>
    0 讨论(0)
  • 甜味超标
    2021-01-22 15:31

    Your test1.php will need to look like this

    <html>
<head>
    <title>Sample</title>
</head>
<body>
    <form action="test1.php" method="post">
        Please enter a number <input type="number" name="userNumber"><br>
        <input type="submit">
    </form>
    <?php
    if(isset($_POST["userNumber"])) { 
        $user_number = $_POST["userNumber"];
        echo "You have chosen $user_number";
    }
    ?>
</body>
</html>
    0 讨论(0)
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