Javascript replace “ ' ” with “ '' ”

Question

I\'m trying to replace the \"\'\" character with the \"\'\'\" string using the replace method, like this:

temp.replace(\"\\\'\", \"\'\'\");

but

Answer 1

The problem is that

temp.replace("\'", "''");

will only replace the first instance of '. To fix this, do the following instead

temp.replace(/'/g, "''"));

This will ensure it goes though and replaces all instances of the single quote instead of just the first.

Answer 2

The trick is quoting each string with the other quote character:

temp.replace(/'/g, '"');

Edit: Ben Lee is correct about the regex, updated above. However, I still gather it that you want to replace with " (one double quote), not '' (two single quotes).

Answer 3

Have you simply tried this?

temp.replace("'", "''");

Answer 4

You're actually trying to replace (\'), not just the single quote character. There is no need to escape a single quote in a string delimited by double quotes, because they don't signify the end of a string...

Replace will only replace the first quote matched, unless you're using our old friend Regexp. The downside being Regular Expressions tend to be slow. I haven't checked to see which is faster, but you could try using split:

var chunks = temp.split("'").join("''");

test = "string cont'aining single 'quotes".split("'").join("''");//in firebug console
//returns "string cont''aining single ''quotes" as expected

Answer 5

So it's basically changing the single quote character with 2 single quote characters, right? If that's the case you might wanna use the global flag, g at the end of yoir Regular Expression and assing it back to your value (temp)

temp = temp.replace(/'/g,"''");

Answer 6

while (str.indexOf("'") >= 0)
    {
        var newStr = str.replace("'", "\"");
        str = newStr;
    }