I\'m writing a simple For loop in Python. Is there a way to break the loop without using the \'break\' command. I would think that by setting count = 10 that the exit condition
As your question states NOTE: Part of the challenge is to use the FOR loop, not the WHILE loop and you don't want to use break
, you can put it in a function and return when the correct number is guessed to break the loop.
import random
def main():
guess_number = 0
count = 0
rand_number = 0
rand_number = random.randint(0, 10)
print("The guessed number is", rand_number)
for count in range(0, 5):
guess_number = int(input("Enter any number between 0 - 10: "))
if guess_number == rand_number:
print ("You guessed it!")
return
else:
print("Try again...")
For loops in Python work like this.
You have an iterable object (such as a list
or a tuple
) and then you look at each element in the iterable, storing the current value in a specified variable
That is why
for i in [0, 1, 2, 3]:
print item
and
for j in range(4):
print alist[j]
work exactly the same. i
and j
are your storage variables while [0, 1, 2, 3]
and range(4)
are your respective iterables. range(4)
returns the list [0, 1, 2, 3]
making it identical to the first example.
In your example you try to assign your storage variable count
to some new number (which would work in some languages). In python however count
would just be reassigned to the next variable in the range
and continue on. If you want to break out of a loop
break
. This is the most pythonic wayreturn
a value in the middle (I'm not sure if this is what you'd want to do with your specific program)try/except
block and raise an Exception
although this would be inappropriateAs a side note, you may want to consider using xrange() if you'll always/often be breaking out of your list early.
The advantage of xrange() over range() is minimal ... except when ... all of the range’s elements are never used (such as when the loop is usually terminated with break)
As pointed out in the comments below, xrange
only applies in python 2.x. In python 3 all range
s function like xrange
The for
loop that you have here is not quite the same as what you see in other programming languages such as Java and C. range(0,5)
generates a list, and the for
loop iterates through it. There is no condition being checked at each iteration of the loop. Thus, you can reassign the loop variable to your heart's desire, but at the next iteration it will simply be set to whatever value comes next in the list.
It really wouldn't make sense for this to work anyway, as you can iterate through an arbitrary list. What if your list was, instead of range(0,5)
, something like [1, 3, -77, 'Word', 12, 'Hello']
? There would be no way to reassign the variable in a way that makes sense for breaking the loop.
I can think of three reasonable ways to break from the loop:
break
statement. This keeps your code clean and easy to understandfor
loops.return
statement to break out. This also allows you to break out of more than one for
loop.One additional way (at least in Python 2.7) that you can break from the loop is to use an existing list and then modify it during iteration. Note that this is a very bad way to it, but it works. I'm not sure that this will this example will work in Python 3.x, but it works in Python 2.7:
iterlist = [1,2,3,4]
for i in iterlist:
doSomething(i)
if i == 2:
iterlist[:] = []
If you have doSomething
print out i
, it will only print out 1 and 2, then exits the loop with no error. Again, this is a bad way to do it.
As others have stated the Python for loop is more like a a traditional foreach loop in the sense that it iterates over a collection of items, without checking a condition. As long as there is something in the collection Python will take them, and if you reassign the loop variable the loop won't know or care.
For what you are doing, consider using the for ... break ... else syntax as it is more "Pythonic":
for count in range(0, 5):
guess_number = int(input("Enter any number between 0 - 10: "))
if guess_number == rand_number:
print("You guessed it!")
break
else:
print("Try again...")
else:
print "You didn't get it."
You can use while
:
times = 5
guessed = False
while times and not guessed:
guess_number = int(input("Enter any number between 0 - 10: "))
if guess_number == rand_number:
print("You guessed it!")
guessed = True
else:
print("Try again...")
times -= 1
What @Rob Watts said: Python for loops don't work like Java or C for loops. To be a little more explicit...
The C "equivalent" would be:
for (count=0; count<5; count++) {
/* do stuff */
if (want_to_exit)
count=10;
}
... and this would work because the value of count
gets checked (count<5
) before the start of every iteration of the loop.
In Python, range(5)
creates a list [0, 1, 2, 3, 4]
and then using for
iterates over the elements of this list, copying them into the count
variable one by one and handing them off to the loop body. The Python for
loop doesn't "care" if you modify the loop variable in the body.
Python's for
loop is actually a lot more flexible than the C for
loop because of this.