Loop Issue Counting Year In PHP

Question

I have created a loop which will display date 2004 to 2014 in a formatted way. But the problem is, it is showing 204 instead of 2004 and continue this till 209.. So, how to show

Answer 1

According to your code, you can try this. Though its not a standard way:

<?php
$yar = 4;
while ($yar <= 9) {
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Jan 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Feb 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Mar 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Apr 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax May 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Jun 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Jul 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Aug 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Sep 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Oct 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Nov 200$yar <br>";
        $ax++;
    }
    $ax = 1;
    while ($ax <= 31) {
        echo "$ax Dec 200$yar <br>";
        $ax++;
    }
    $yar++;
}
$yr = 10;
while ($yr <= 14) {
    $x = 1;
    while ($x <= 31) {
        echo "$x Jan 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Feb 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Mar 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Apr 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x May 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Jun 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Jul 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Aug 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Sep 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Oct 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Nov 20$yr <br>";
        $x++;
    }
    $x = 1;
    while ($x <= 31) {
        echo "$x Dec 20$yr <br>";
        $x++;
    }
    $yr++;
}
?>

Answer 2

You could do it also with a (Quite) different Structure:

<?php
    function displayDate($yr, $yrMax) {
        if ($yr > $yrMax) {
            return true;
        }
        else {
            displayMonth($yr);
            $yr++;
            return displayDate($yr, $yrMax);
        }
    }
    function displayMonth($yr, $month = 1) {
        if ($month > 12) {
            return true;
        }
        else {
            displayDay($yr, $month);
            return displayMonth($yr, $month+1);
        }
    }
    function displayDay($yr, $month, $day = 1, $dayMax = 31) {
            if ($day > $dayMax) {
                return true;
            } else {
                $displayMonth = getMonth($month);
                echo "$day $displayMonth $yr<br>";
                $day++;
                return displayDay($yr, $month, $day, $dayMax);
            }
    }
    function getMonth($month) {
        switch($month){
            case 1:
                return 'Jan';
            case 2:
                return 'Feb';
            case 3:
                return 'Mar';
            case 4:
                return 'Apr';
            case 5:
                return 'May';
            case 6:
                return 'Jun';
            case 7:
                return 'Jul';
            case 8:
                return 'Aug';
            case 9:
                return 'Sep';
            case 10:
                return 'Oct';
            case 11:
                return 'Nov';
            case 12:
                return 'Dec';
        }
    }

            //Here we call the structure build above.
    if (displayDate(2004, 2014)) {
        echo 'Done';
    }
?>

Answer 3

All you need is one loop

$start = 2004;
$end = 2014;

$dateTime = new DateTime();
$dateTime->setDate($start, 1, 1);

echo "<pre>";
while ( $dateTime->format("Y") <= $end ) {
    echo $dateTime->format("d M Y"), PHP_EOL;
    $dateTime->modify("+1 day");
}

Answer 4

I am not sure why are you doing this by so many loops, use this instead of $yr and you will get the correct year printed:

 str_pad($yr, 2, '0', STR_PAD_LEFT);

Best