making text appear delayed

Question

I want to make text appear in the following way:

H
wait 0.1 seconds
He
wait 0.1 seconds
Hel
wait 0.1 seconds
Hell
wait 0.1 seconds
Hello

But I\

Answer 1

Use the Thread.sleep function to pause execution.

System.out.print("H");
Thread.sleep(1000);
System.out.print("E");
...etc

Of course, you'd probably want to put all of that into a loop, but Thread.sleep is what you want

Answer 2

Try this:

 try {
  Thread.sleep(timeInMiliseconds); // In your case it would be: Thread.sleep(100);
} catch (Exception e) {
    e.printStackTrace();
}

Answer 3

String text = "Hello";

for(int i=1; i<=text.length();i++){
   System.out.println(text.substring(0, i));
    try {
       Thread.sleep(100); 
    } catch (Exception e) {
       e.printStackTrace();
    }
}

Edit: if you want only 1 character by 1, than:

for(int i=0; i<text.length();i++){
   System.out.print(""+text.characterAt(i));
    try {
       Thread.sleep(100); 
    } catch (Exception e) {
       e.printStackTrace();
    }
}

Answer 4

You can print each letter in 0.1s interval using Thread.sleep or more readable way (at least for me) using TimeUnit.MILLISECONDS.sleep for example

print first letter;
TimeUnit.MILLISECONDS.sleep(100);
print second letter
TimeUnit.MILLISECONDS.sleep(100);
...

[Update]

I'm hoping that I will be able to do it in a way that doesn't require me to make a System.out.print(); for each letter.

I don't see any reason not to do it this way.

public static void main(String[] args) throws Exception {
    printWithDelays("HELLO", TimeUnit.MILLISECONDS, 100);
}

public static void printWithDelays(String data, TimeUnit unit, long delay)
        throws InterruptedException {
    for (char ch : data.toCharArray()) {
        System.out.print(ch);
        unit.sleep(delay);
    }
}