Why does printf show an additional % character in the terminal?

Question

I started learning to code with the C language. I wrote the following program:

#include

int main()
{
   int count = 0;

   printf("Count %d.&         


        

Answer 1

Your shell is likely adding a % sign to indicate that the line was not properly terminated. Many shells do this, like for example ZSH or Fish.

Just add a \n to your call to printf and you're good.