jQuery keep show hide state based on select option

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梦谈多话
梦谈多话 2021-01-22 01:54

I have drop down select and show hide other fields (within divs) based on option selected in the dropdown list.

This code works fine and show hide based on selection but

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3条回答
  • 2021-01-22 02:15

    Assign an common class to all the div's that holds the content

    show hide based on selection but when I load the page all fields are visible

    <div id="row1_col1_layout_type2" class="content">
                                            ^
                                            ----- This to target with a single selector
    

    CSS

    .content{
       display :none;
    }
    

    And in the JS just trigger the change event so as to show the div with option that is selected

    $('#row1_layout_options').change(function() {
       $('.content').hide();
       $('#row1_col1_' + $(this).val()).show();
       // Sen d an ajax request to save the value in DB
       $.ajax({
    
       });
    }).change();  <--- Trigger the event
    

    Next is the Page Reload. Web is stateless . So it will not remember the previous state. The only thing you can do is persist the value after page refresh. Maybe in as a cookie, Local Storage or saving it on server and retrieving it back.. Check Fiddle

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  • 2021-01-22 02:21

    I would suggest adding a class for your loaded content which will make them hidden.

    HTML

    <select id="row1_layout_options" name="row1_layout_options">
        <option value="Select Layout Type">Select Layout Type</option>
        <option value="layout_type1">layout_type1</option>
        <option value="layout_type2">layout_type2</option>
        <option value="layout_type3">layout_type3</option>
        <option value="layout_type4">layout_type4</option>
        <option value="layout_type5">layout_type5</option>
        <option value="layout_type6">layout_type6</option>
        <option value="layout_type7">layout_type7</option>
        <option value="layout_type8">layout_type8</option>
    </select>
    
    <div id="layouts">
        <div id="row1_col1_layout_type2">
            <input type="text" class="qa-form-tall-text" value="" name="q2am_fp_row1_col1_layout_type2">
        </div>
    </div>
    

    JS

    $('#row1_layout_options').change(function() {
       $('#layouts>div.selected').removeClass('selected');
       $('#row1_col1_' + $(this).val()).addClass('selected');
    });
    

    CSS

    #layouts>div{
        display:none;
    }
    
    #layouts>div.selected{
        display:block;
    }
    

    EDIT : Saving selected

    As for saving the selected option you have these non exhaustive list of solution :

    • HTML5 localstorage, you can use localStorage which is a javascript accessible store that is flushed like cookies. I wouldn't recommend that one I found it very much unreliable.
    • Server side persistence. Basically when you set an option as selected you send a query to a webservice that will save the state somewhere (DB, object instance etc...)
    • URL modification. that's not really a persistence solution but it could match the need sometimes. You can retrieve a value in the URL parameter section like http://localhost/mysite?selectedId=2. This way you can have the information directly within the link. Easier to share the state.
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  • 2021-01-22 02:39

    Just do the same in document.ready

    $(document).ready(function(){
        $('#row1_col1_layout_type1, #row1_col1_layout_type2, #row1_col1_layout_type3').hide();
        $('#row1_col1_' + $('#row1_layout_options').val()).show();
    
        $('#row1_layout_options').on('change',function() {
           $('#row1_col1_layout_type1, #row1_col1_layout_type2, #row1_col1_layout_type3').hide();
           $('#row1_col1_' + $(this).val()).show();
        });
    });
    

    here is the fiddle

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