given matrix:
x = matrix([[ 0.9, 0.14], [ 0.15, 0.8]])
how can you make the first column, x[:,0]
, into a diagonal matrix in nump
numpy.diag( x.A[ :, 0 ] )
should do it.
The difference between a matrix
and an array
is crucial here. You won't get the same result from just numpy.diag( x[ :, 0 ] )
. x.A
is a shorthand for numpy.asarray( x )
when x
is a matrix
.
So by the same token, to answer your question precisely I guess I shouldn't forget convert the answer from an array
back to a matrix
:
numpy.matrix( numpy.diag( x.A[ :, 0 ] ) )
There is a diagflat
that 'Create a two-dimensional array with the flattened input as a diagonal.'. It both ravels
the input, and wraps the result in np.matrix
(matching the input array type):
In [122]: np.diagflat(x[:,0])
Out[122]:
matrix([[ 0.9 , 0. ],
[ 0. , 0.15]])
So it's doing all the work of jez
answer, just wrapping it in a generalized function:
np.matrix(np.diag(np.asarray(x[:,0]).ravel()))