Javascript regex to extract all characters between quotation marks following a specific word

Question

I have the text:

s.events=\"event3\"
s.pageName=\"Forum: Index\"
s.channel=\"forum\"
s.prop1=\"Forum: Index\"
s.prop2=\"Index Page\"
s.prop36=\"\"
s.prop37=\"\"
         


        

Answer 1

Use this:

var myregex = /s\.prop42="([^"]*)"/;
var matchArray = myregex.exec(yourString);
if (matchArray != null) {
    thematch = matchArray[1];
} 

In the regex demo, look at the capture group in the right pane.

Explanation

• s\.prop42=" matches s.prop42=" (but we won't retrieve it)
• The parentheses in ([^"]*) capture any chars that are not a " to Group 1: this is what we want
• The code gets the Group 1 capture

Answer 2

Can't comment on above answer, but I think the regex is better with .* like so:

var myregex = /s\.prop42="(.*)"/;
var matchArray = myregex.exec(yourString);
if (matchArray != null) {
    thematch = matchArray[1];
}