How to check if a list is in another list with the same order python [duplicate]

Answer 1

Python 2:

def is_a_in_x(A, X):
  for i in xrange(len(X) - len(A) + 1):
    if A == X[i:i+len(A)]: return True
  return False

Python 3:

def is_a_in_x(A, X):
  for i in range(len(X) - len(A) + 1):
    if A == X[i:i+len(A)]: return True
  return False

Answer 2

One possible solution if your numbers are always three digit:

x = ['123', '456', '789']

A = ['123', '456']
''.join(A) in ''.join(x)

B = ['456', '123']
''.join(B) in ''.join(x)

C = ['123', '789']
''.join(C) in ''.join(x)

Although, prone to bugs for example:

D = ['1', '23']
''.join(D) in ''.join(x)


outputs True

Answer 3

def foo(your_list, your_main_list):
    list_len = len(your_list)
    for i, item in enumerate(your_list):
        if your_main_list[i] == item: 
            if i + 1 == list_len:
                return True
        else:
            return False