Unparsable date exception

Question

I\'m currently working on some simple project in Java and I have date in the following string:

String dateString = \"Sun 7/14 03:44 AM 2013\";


        

Answer 1

I tried this out and the following worked,

        String stringDate = "Sun 7/14 03:44 AM 2013";
        DateFormat format = new SimpleDateFormat("EEE MM/dd hh:mm a yyyy");

        System.out.println("Parsed Date = "+format.parse(stringDate));

The output was as follows

Parsed Date = Sun Jul 14 03:44:00 BST 2013

Answer 2

The modern answer for the sake of completeness. While the other answers were good answers in 2013, Date, DateFormat and SimpleDateFormat are now long outdated, and I recommend you replace them with their modern counterparts:

    DateTimeFormatter parser 
            = DateTimeFormatter.ofPattern("EEE M/dd hh:mm a yyyy", Locale.ENGLISH);
    LocalDateTime ldt = LocalDateTime.parse(dateString, parser);

The result is a LocalDateTime of 2013-07-14T03:44 as expected.

The format pattern string is still the same, and the need for an English language locale is the same.

Answer 3

Certain fields such as the day of week fields and/or AM/PM marker may not match those from your default Locale. ParseException has the method getErrorOffset to determine exactly where the pattern does not match.

try

DateFormat format = 
                new SimpleDateFormat("EEE M/dd hh:mm a yyyy", Locale.ENGLISH);

Answer 4

It is important to add Locale as you are parsing language day of week names.

String dateString = "Sun 7/14 03:44 AM 2013";
DateFormat format = new SimpleDateFormat("EEE M/dd hh:mm a yyyy", Locale.US);
Date d = format.parse(dateString);

Answer 5

SimpleDateFormat formatter = new SimpleDateFormat("/* type your own format*/");



  String formattedDate = formatter.format(todaysDate);

  System.out.println("Formatted date is ==>"+formattedDate);

try this code