I have an array with french strings let say: \"égrener\" and \"exact\" I would like to sort it such as égrener is the first. When I do:
NSSortDescriptor *descrip
There’s a convenience method in NSString
that lets you do this type of sorting easily:
NSArray *sortedArray = [myArray sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];
NSString
’s underlying comparison method (compare:options:range:locale:) gives you even more options of how sorting should be done.
Edit: Here’s the long story:
First, define a comparison function. This one is good for natural string sorting:
static NSInteger comparator(id a, id b, void* context)
{
NSInteger options = NSCaseInsensitiveSearch
| NSNumericSearch // Numbers are compared using numeric value
| NSDiacriticInsensitiveSearch // Ignores diacritics (â == á == a)
| NSWidthInsensitiveSearch; // Unicode special width is ignored
return [(NSString*)a compare:b options:options];
}
Then, sort the array.
NSArray* myArray = [NSArray arrayWithObjects:@"foo_002", @"fôõ_1", @"fôõ_3", @"foo_0", @"foo_1.5", nil];
NSArray* sortedArray = [myArray sortedArrayUsingFunction:comparator context:NULL];
The array in the example contains some funny characters: Numbers, diacritical marks, and some characters from unicode range ff00. The last character type looks like an ASCII character but is printed in a different width.
The used comparison function handles all cases in human predictable way. The sorted array has the following order:
foo_0
fôõ_1
foo_1.5
foo_002
fôõ_3