Apologies for the confusing title, but I don\'t know how to express my problem otherwise. In R, I have the following problem which I want to solve:
x <- seq(1
Similar to @VincentGuillemot's answer, but in functional programming style. Uses purrr
package:
i <- z
map(p, function(x) { i <<- i[-min(which(i == x))]})
i
> i
[1] 1 1 1 1 1 1 1 0 0 0 0 0 0 0
There might be numerous better ways to do it:
i <- z
for (val in p) {
if (val %in% i) {
i <- i[ - which(i==val)[1] ]
}
}
Another solution that I like better because it does not require a test (and thanks fo @Franck's suggestion):
for (val in p)
i <- i[ - match(val, i, nomatch = integer(0) ) ]