Programmatically perform click on a DataGridView Button Cell from another Button

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长情又很酷
长情又很酷 2021-01-21 17:16

I have a question regarding DataGridView control in .NET.

I inserted a DataGridView from the toolbox and I connected it with a database that I

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  • 2021-01-21 17:55

    You can use either of the following options:

    • Calling the event handler of CellContentClick like a normal method by creating an instance of DataGridViewCellEventArgs and pass it to the event handler method.
    • Or put the whole logic inside a method and call that method whenever you need, from CellContentClick of the DataGridView or Click of the button.

    VB.NET

    Example 1 - Perform Click for DataGrdiView Button Cell by calling the event handler

    To programmatically click on button in specific row, you can call the method that you created as event handler of CellContentClick event, using suitable DataGridViewCellEventArgs as e and your DataGridView as sender:

    Private Sub AnotherButton_Click(sender As Object, e As EventArgs) _
        Handles AnotherButton.Click
        ' zero based ColumnIndex of your button column= 3 (for example)
        ' zero based RowIndex that you want to click on its button column = 2 (for example)
        Dim arg = New DataGridViewCellEventArgs(3, 2) 
        DataGridView1_CellContentClick(DataGridView1, arg)
    End Sub
    
    Private Sub DataGridView1_CellContentClick(sender As Object, _
        e As DataGridViewCellEventArgs) Handles DataGridView1.CellContentClick
        MessageBox.Show(e.RowIndex.ToString())
    End Sub
    

    Example 2 - Putting the logic in another method and call the method when you need

    As another option you can put the logic related to click on a cell button in a method, dependent from Cell and Row objects and only pass suitable values to that method. Then you can call the method wherever you need.

    Private Sub DoSomething(rowIndex as Integer, columnIndex as Integer)
        MessageBox.Show(rowIndex.ToString())
    End Sub
    
    Private Sub AnotherButton_Click(sender As Object, e As EventArgs) _
        Handles AnotherButton.Click
        ' zero based ColumnIndex of your button column= 3 (for example)
        ' zero based RowIndex that you want to click on its button column = 2 (for example)
        DoSomething(2, 3) 
    End Sub
    
    Private Sub DataGridView1_CellContentClick(sender As Object, _
        e As DataGridViewCellEventArgs) Handles DataGridView1.CellContentClick
        DoSomething(e.RowIndex, e.ColumnIndex)
    End Sub
    

    C#

    Example 1 - Perform Click for DataGrdiView Button Cell by calling the event handler

    To programmatically click on button in specific row, you can call the method that you created as event handler of CellContentClick event, using suitable DataGridViewCellEventArgs as e and your DataGridView as sender:

    private void anotherButton_Click(object sender, EventArgs e)
    {
        ' zero based ColumnIndex of your button column= 3 (for example)
        ' zero based RowIndex that you want to click on its button column = 2 (for example)
        var arg = new DataGridViewCellEventArgs(3, 2); 
        aataGridView1_CellContentClick(dataGridView1, arg);
    }
    
    private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
    {
        MessageBox.Show(e.RowIndex.ToString());
    }
    

    Example 2 - Putting the logic in another method and call the method when you need

    As another option you can put the logic related to click on a cell button in a method, dependent from Cell and Row objects and only pass suitable values to that method. Then you can call the method wherever you need.

    private void DoSomething(int rowIndex, int columnIndex)
    {
        MessageBox.Show(rowIndex.ToString());
    }
    
    private void anotherButton_Click(object sender, EventArgs e)
    {
        ' zero based ColumnIndex of your button column= 3 (for example)
        ' zero based RowIndex that you want to click on its button column = 2 (for example)
        DoSomething(2, 3); 
    }
    
    private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
    {
        DoSomething(e.RowIndex, e.ColumnIndex);
    }
    
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  • 2021-01-21 17:55

    If you want to generate programmatically click on DataGridViewButtonCell instance, you can use DataGridViewCell.AccessibilityObject property and call DoDefaultAction method.

    Something like this (sorry for C#, I'm sure you can translate it to VB):

    DataGridViewButtonCell otherCell = ...;
    otherCell.AccessibilityObject.DoDefaultAction();
    

    Test:

    using System;
    using System.Linq;
    using System.Windows.Forms;
    
    namespace Samples
    {
        static class Program
        {
            [STAThread]
            static void Main()
            {
                Application.EnableVisualStyles();
                Application.SetCompatibleTextRenderingDefault(false);
                var form = new Form();
                var grid = new DataGridView { Dock = DockStyle.Fill, Parent = form, AutoGenerateColumns = false };
                var col0 = new DataGridViewTextBoxColumn { Name = "Col0", HeaderText = "Col0", DataPropertyName = "Col0" };
                var col1 = new DataGridViewButtonColumn { Name = "Col1", HeaderText = "Col1", DataPropertyName = "Col1" };
                grid.Columns.AddRange(new DataGridViewColumn[] { col0, col1 });
                grid.CellContentClick += (sender, e) =>
                {
                    MessageBox.Show("Clicked Cell[" + e.RowIndex + "," + e.ColumnIndex + "]");
                };
                grid.DataSource = Enumerable.Range(0, 10).Select(n => new { Col0 = "Cell[" + n + ",0]", Col1 = "Cell[" + n + ",1]" }).ToList();
                var button = new Button { Dock = DockStyle.Bottom, Parent = form, Text = "Click" };
                button.Click += (sender, e) =>
                {
                    var cell = grid.CurrentRow.Cells[col1.Index];
                    cell.AccessibilityObject.DoDefaultAction();
                };
                Application.Run(form);
            }
        }
    }
    
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