Sort dictionary elements in list

Question

For this list,

[{u\'status\': u\'Active\', u\'name\': u\'X\', u\'orgID\': u\'109175\', u\'type\': u\'Created Section\',\'class\': \'addbold\'} , 
{u\'status\':          


        

Answer 1

sorted or list.sort accept optional key function parameter. The return value of the function is used to compare elements order.

>>> lst = [...]
>>> sorted(lst, key=lambda x: x['name'])
[{u'status': u'Active', u'type': u'Created Section', u'orgID': u'109175', u'name': u'A', 'class': 'addbold'},
 {u'status': u'Active', u'type': u'Created Section', u'orgID': u'109175', u'name': u'D', 'class': 'addbold'},
 {u'status': u'Active', u'type': u'Created Section', u'orgID': u'109175', u'name': u'G', 'class': 'addbold'},
 {u'status': u'Active', u'type': u'Created Section', u'orgID': u'109175', u'name': u'X', 'class': 'addbold'}]

operator.itemgetter('name') can be used in place of the lambda function.

import operator
sorted(lst, key=operator.itemgetter('name'))