I have a python code like below: My question is why the matched variable is [\' \']? (I used the regex in regexpal.com, it can find the right result |Name=A. Johnson | there)
matched = re.findall("\|?\s*[nN]ame\s*=([a-zA-Z\.\s]+)\|?",a,re.I)
print matched
output:
['A. Johnson ']
Looks to be how it's handling grouping. As a simpler example, look at the difference between the output of the following lines of code:
re.findall("c(a)*t", "hi caaat hi")
re.findall("c(a*)t", "hi caaat hi")
It looks like the code you want would be more like:
re.findall("\|\s*name\s*=([^\|\}]*)", a, re.I)
You'll want (.*?)
, not (.)*?
—the latter (what you have) will only capture a single character, even if it consumes more than a single one. A capture group will only be returned once even if the group itself has a repeat; so the latter captures a single character (.)
despite its repeat.
If you move the repeat into the capture group with (.*?)
, you'll get more than a single character in the return.