Find “carriage return” in a mail.body

Question

I have mails like this :

Hello,

Please note we did ... at 16h15

Actions done: Rebuilding etc

sincerely

Answer 1

The carriage return in the email body is usually vbNewline

This is how I usually do it

Sub Sample()
    Dim sBody As String
    Dim MyAr
    Dim i As Long

    '
    '~~> Rest of your code
    '

    sBody = oMail.Body

    '~~> For testing purpose
    'sBody = "Hello," & vbNewLine & vbNewLine
    'sBody = sBody & "Please note we did ... at 16h15" & vbNewLine & vbNewLine
    'sBody = sBody & "Actions done: Rebuilding etc" & vbNewLine & vbNewLine
    'sBody = sBody & "Sincerely"

    '~~> Split the email body on vbnewline and store it in array
    MyAr = Split(sBody, vbNewLine)

    '~~> Loop through array
    For i = LBound(MyAr) To UBound(MyAr)
        '~~> Check if the line has "Actions done:"
        If InStr(1, MyAr(i), "Actions done:") Then
            '~~> This would give you "Rebuilding etc"
            '~~> Split the line on "Actions done:"
            '~~> You will get an array. Ar(0) will have "Actions done:"
            '~~> And Ar(1) will have what you are looking for so we use
            '~~> Split()(1) directly to access that item
            MsgBox Split(MyAr(i), "Actions done:")(1)
            Exit For
        End If
    Next i
End Sub

Edit

ANOTHER WAY

Answer 2

Try this:

TechnicPosition = InStr(1, .Body, "Actions done: ")
TechnicEndPosition = InStr(TechnicPosition, .Body, Chr(10))
TechnicAction = Mid(.Body, TechnicPosition + 14, TechnicEndPosition - TechnicPosition - 14)

Answer 3

Loop through the body to see what the character is:

For i = 1 To Len(.Body)
    If Not Mid(.Body, i, 1) Like "[A-Za-z0-9,'?!"".:]" Then
        Debug.Print Asc(Mid(.Body, i, 1))
    End If
Next

Once you've found the Asc() value, split the body on it and return the second index:

TechnicAction = Split(.Body, Asc(10))(1) '// Or whatever Asc() is required