Find and replace specific hash and it's values within array

Question

What is the most efficient method to find specific hash within array and replace its values in-place, so array get changed as well?

I\'ve got this code so far, but in a

Answer 1

This will do what you're after looping through the records only once:

array.each { |hash| hash[:parameters][:omg] = "triple omg" if hash[:id] == 1 }

You could always expand the block to handle other conditions:

array.each do |hash| 
  hash[:parameters][:omg] = "triple omg" if hash[:id] == 1
  hash[:parameters][:omg] = "quadruple omg" if hash[:id] == 2
  # etc
end

And it'll remain iterating over the elements just the once.

It might also be you'd be better suited adjusting your data into a single hash. Generally speaking, searching a hash will be faster than using an array, particularly if you've got unique identifier as here. Something like:

{ 
  1 => {
    parameters: {
      omg: "lol"
    },
    options: {
      lol: "omg"
    }
  },
  2 => {
    parameters: {
      omg: "double lol"
    },
    options: {
      lol: "double omg"
    }
  } 
}

This way, you could just call the following to achieve what you're after:

hash[1][:parameters][:omg] = "triple omg"

Hope that helps - let me know how you get on with it or if you have any questions.