Semicolon after if condition in PHP - code still works

Question

consider the following code...

if ($condition); // <-- do not miss semicolon here!
{
    //...
}

After that code inside block works. Can som

Answer 1

I would recommend you to read the manual here:

http://php.net/manual/en/control-structures.if.php

To you question directly why: you don't get a syntax error?
->Simple because there is no syntax error!

Your code is correct and means this:

if ($condition) ;
//  ^condition  ^if true execute that line

//same as
if ($condition)
    ;

//same example with other line if the condition is true
if ($condition) echo "true";

if ($condition)
    echo "true";

So your line which gets executed if the condition is true is this: ; and means nothing.

it's the same as: ;;;;; It's just nothing!

In most of the time you use a if statement like this:

if ($condition)
    echo $result;


if ($condition) {
    echo $result;
}

if ($condition) echo $result;

Answer 2

becuse you can write any code inside { } without if

check this example:

<?php

{
    echo 'Hi Man'; // it print Hi Man (without using if statment)
}

?>