convert the value of dictionary from list to float

Question

I have a dictionary named \"location\" like this:

{
    \'WA\': [
        \'47.3917\',
        \'-121.5708\'
    ],
    \'VA\': [
        \'37.7680\',
        \'         


        

Answer 1

Your problem is in here: float(location[key][0,1])

# float objects are length 1
for key in location.keys():
    location[key] = [float(location[key][0]),float(location[key][1])]
print location

Answer 2

You can use a list comprehension within a dictionary comprehension. Since you need both keys and values, use dict.items to iterate key-value pairs:

res = {k: [float(x) for x in v] for k, v in locations.items()}

map works more efficiently with built-ins, so you may wish to use:

res = {k: list(map(float, v)) for k, v in locations.items()}

Or, since you have coordinates, for tuple values:

res = {k: tuple(map(float, v)) for k, v in locations.items()}

The problem with your logic location[key][0,1] is Python lists do not support vectorised indexing, so you need to be explicit, e.g. the verbose [float(location[key][0]), float(location[key][1])].

Answer 3

You can use dictionary comprehension to construct a dictionary which has the values converted to floats, like this

print {k:map(float, locations[k]) for k in locations}

As suggested by @Grijesh in the comments section, if you are using Python 3,

print({k:list(map(float, locations[k])) for k in locations})