how to prevent losing double quotes in argv?

Question

Ok, I know I can do loop like this:

for (int i=1; i<=argc-1;i++) {
  cout << argv[i] << endl;
}

But this way double quotes are l

Answer 1

It's the shell that removes the quotes. If you want the shell to pass the quotes to you, you have to escape them:

$ ./my-program \"hello\ world\"

Note that I escape the space as well, to make it one argument.

Answer 2

When you need the original command line, your can use the GetCommandLine() API function.