How to load a view based on condition in Controller (Codeigniter)

Question

I\'m new to codeigniter. I\'m trying to make a simple site, that will get its \"settings\" on the database, if the site is enabled (1) or not (0).

I\'m trying to determi

Answer 1

MODEL Here you need to fetch single row by using $query->row(); and pass it to controller

function getsetting() {
$this->db->select("site");
$this->db->from('configuration');
$query = $this->db->get();
$ret = $query->row();
return $ret->site;
}

As you describe in your question

the values [null or 1]

Controller

function your_controler() {

        $this->load->model('model_file');

        $site = $this->model_file->getsetting();
        if(isset($site) && $site==1){// your condition here
        $this->load->view('index', $data);
        }else{
            $this->load->view('maintenance', $data)

        }

    }

Answer 2

Use something like this for your controller:

$setting = $this->modelName->getsetting();

if($setting['maintenance'] == 1){

    $this->load->view('maintenance', $data);

} else {

     $this->load->view('index' $data);

}

Be sure to replace 'modelName' with the name of the 'getsetting' method's model.

Answer 3

If you want to disable all method access in maintenance mode, do something like below in your controller's constructor,

public function __construct()
{
    parent::__construct();
    $site = $this->Datamodel->getsetting();
    if(isset($site->site) && $site->site==1)
    {
        $this->load->view('index');
        die;
    }
}