How to receive input as yyyyMMddHHmm format in java?

Question

SimpleDateFormat sdf = new SimpleDateFormat(\"yyyyMMddHHmm\");
java.util.Date parsedDate = sdf.parse(\"201212130900\");
java.sql.Timestamp timestamp = new java.sql.Times         


        

Answer 1

I have solved the above problem.

I converted the date to "yyyyMMdd" format and converted the time in "HHmm" format, storing them as 2 different strings.

Answer 2

In java, to get a formated date, you would do the following:

SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMddHHmm");
String sdf.format(myDate);

There are loads of options in SimpleDateFormat. I have attached the JavaDoc for you.

Answer 3

Your conversion from string to timestap is OK.(I tested and works).

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You problem may be in the time zone or something. Try to use this method instead,

setTimestamp(int parameterIndex, Timestamp x, Calendar cal) 

Example:

setTimestamp(1, timestamp , Calendar.getInstance(TimeZone.getTimeZone("UTC")))

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UPDATED: (table1.table_key is an CHAR(24))

You should give you date from java in a String, assuming key_value is formatted as "yyyyMMddhhmm"... (for obvious reasons other format will not work)

Other option is in your query convert key_value to TIMESTAMP

Try: (I'm assuming you are working with oracle db, and I do some search)

1) Do a "cast" to timestamp

"select count(*) as counter from table1 where timestamp(table_key) > ?"

2)Using http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions193.htm . I do not know if you can do something like this:

"select count(*) as counter from table1 where TO_TIMESTAMP(table_key,'YYYYMMDDHHMMHH24MI') > ?"