Slice a binary number into groups of five digits

Question

Is there any neat trick to slice a binary number into groups of five digits in python?

\'00010100011011101101110100010111\' => [\'00010\', \'00110\', \'10111\', ... ]

Answer 1

My question was duplicated by this one, so I would answer it here.

I got a more general and memory efficient answer for all this kinds of questions using Generators

from itertools import islice
def slice_generator(an_iter, num):
    an_iter = iter(an_iter)
    while True:
        result = tuple(islice(an_iter, num))
        if not result:
           return
        yield result

So for this question, We can do:

>>> l = '00010100011011101101110100010111'
>>> [''.join(x) for x in slice_generator(l,5)]
['00010', '10001', '10111', '01101', '11010', '00101', '11']