Mysqli DELETE QUERY not working in PHP Script

Question

Im using the following code to remove an entry from a table what i want to do is to check if any value was deleted from the table.If one value is deleted,the script should print

Answer 1

How about using execption. I also changed the code a little bit.

<?php
$mysqli = new mysqli("SQLHOST.COM", "CLIENT", "PASSWORD", "DNAME", 1234);
$connection = mysqli_connect('SQLHOST', 'CLIENT', 'PASSWORD') or die(mysqli_error());
try {
    $select_db = mysqli_select_db('DBNAME', $connection);
    if (!$select_db) {
        throw new Exception("Could not connect!");
    }
}
catch (exception $e) {
    echo "Error (File: " . getFile() . ", line " . $e->getLine() . "): " . $e->
        getMessage();
}
$query = mysqli_query('DELETE FROM ktable WHERE code="' . $value . ';"');
    if ($query) {

        printf("Select returned %d rows.\n", $result->num_rows);
        printf($result->num_rows);
        mysqli_close();
    }
?>

Answer 2

what you delete what you need to return is affected_rows http://www.php.net/manual/en/mysqli.affected-rows.php

What you need to Replace

if ($result = $mysqli->query("DELETE FROM ktable WHERE code='value'")) {
    printf("Select returned %d rows.\n", $result->num_rows);


    printf($result->num_rows);
    $result->close();
}

Working Code

$value = ""; // Set To any Value
$mysqli = new mysqli ( "SQLHOST.COM", "CLIENT", "PASSWORD", "DNAME", 1234 );
if ($mysqli->connect_errno) {
    printf ( "Connect failed: %s\n", $mysqli->connect_error );
    exit ();
} else {
    printf ( "cONN Sucees" );
    if ($mysqli->query (sprintf ( "DELETE FROM ktable WHERE code='%s'", mysqli_real_escape_string ( $mysqli, $value ) ) )) {
        printf ( "Affected Rows  %d rows.\n", $mysqli->affected_rows );
    }
}

You should have a working output